The CD4093 CMOS IC (IC1a & b) is configured as
a square-wave oscillator of about 2Hz. IC1 c & d invert this 2Hz signal. These two
complementary square wave voltages are used as the test supply voltage to the Device Under
Test (D.U.T.). Transistor base bias is via a 1000-Ohm resistor. Two red LEDs are
paralleled in �contra� fashion and connected across the output. Current flow through
either led is limited by the 470 Ohm resistor and either LED�s P.I.V. is clamped to
about 1.7v, which is the ON-state voltage of the other LED (being in the conducting
state). With no D.U.T. connected to the tester, and TEST push button pressed, both LEDs
will flash alternately. If a healthy transistor is now connected: during the half-cycle
during which it will be biased ON and therefore heavily conducting, one LED will be
effectively short-circuited and remain dark. On the alternate half-cycle, the polarity of
the applied signal will not cause the D.U.T. To switch ON and current can then flow
through one led causing it to illuminate. This appears as a 2Hz flashing of the LED.
It should therefore be evident that if the D.U.T. is:
1. Shorted; both LEDs will be dark and
2. Open Cct; both LEDs will flash.
The purpose of the two strings of series connected silicon diodes,
connected in series with the D.U.T. may require some explanation: Their function is to
allow only a current pathway through the D.U.T. provided that it is in fact fully
saturated (turned hard-ON) and that insufficient current could flow through parallel
circuit resistances such that one or both of the LEDs would be dark due to this. Remember
this design is called an "in-circuit" tester (no messy de-soldering, to isolate
a suspect faulty semiconductor!). In order to test SCRs and diodes, S1 is thrown to the
appropriate position, in which one of each of the two series connected pair of diodes is
switched out. This is necessary because: the forward ON-state voltage of a healthy diode
or SCR being about 0.7 volt, then three conducting series junctions would present about
2.1 Volt across the LED, which should normally be dark. If you have any questions related
to this project then please refer them to the author Frank V. Hughes